4. Решите уравнение: 1) \frac{x}{6} = 19; 2) \frac{216}{y} = 12; 3) \frac{948}{y-12} = 6.

1) $$\frac{x}{6} = 19$$

$$x = 19 \cdot 6$$

$$x = 114$$

2) $$\frac{216}{y} = 12$$

$$y = \frac{216}{12}$$

$$y = 18$$

3) $$\frac{948}{y-12} = 6$$

$$y - 12 = \frac{948}{6}$$

$$y - 12 = 158$$

$$y = 158 + 12$$

$$y = 170$$

Ответ: 1) 114; 2) 18; 3) 170.