Решите уравнение 1) $$4\frac{3}{8}-x=3\frac{5}{8}$$; 2) 15-x=$$3\frac{1}{8}$$ Найди значение выражения и запиши ответ $$5\frac{47}{71}+1\frac{3}{71}-\frac{63}{71}+2\frac{10}{71} = $$

Решим уравнения.

1) $$4\frac{3}{8}-x=3\frac{5}{8}$$

• $$x = 4\frac{3}{8}-3\frac{5}{8}$$
• $$x = \frac{35}{8}-\frac{29}{8}$$
• $$x = \frac{6}{8}$$
• $$x = \frac{3}{4}$$

2) $$15-x=3\frac{1}{8}$$

• $$x = 15-3\frac{1}{8}$$
• $$x = 14\frac{8}{8}-3\frac{1}{8}$$
• $$x = 11\frac{7}{8}$$

Найдем значение выражения:

$$5\frac{47}{71}+1\frac{3}{71}-\frac{63}{71}+2\frac{10}{71} = $$

• $$5\frac{47}{71}+1\frac{3}{71}+2\frac{10}{71} - \frac{63}{71} = (5+1+2) + (\frac{47}{71}+\frac{3}{71}+\frac{10}{71}) - \frac{63}{71} = $$
• $$= 8 + \frac{60}{71} - \frac{63}{71} = 8 - \frac{3}{71} = 7\frac{71}{71} - \frac{3}{71} = 7\frac{68}{71}$$

Ответ: $$7\frac{68}{71}$$