\[\frac{1}{3}x + \frac{5}{7} = \frac{2}{7} - \frac{1}{9}x\]
\[\frac{1^{\backslash 3}}{3}x + \frac{1}{9}x = \frac{2}{7} - \frac{5}{7}\]
\[\frac{3 + 1}{9}x = - \frac{3}{7}\]
\[\frac{4}{9}x = - \frac{3}{7}\]
\[x = - \frac{3}{7}\ :\frac{4}{9} = - \frac{3}{7} \cdot \frac{9}{4}\]
\[x = - \frac{27}{28}.\]