Решите уравнение 15x^2-4x-3=0.

\[15x^{2} - 4x - 3 = 0\]

\[D = 16 + 180 = 196\]

\[x_{1} = \frac{4 + 14}{30} = \frac{18}{30} = \frac{3}{5} = 0,6;\]

\[x_{2} = \frac{4 - 14}{30} = - \frac{10}{30} = - \frac{1}{3}.\]

\[Ответ:x = - \frac{1}{3};\ \ x = 0,6.\]