Решите уравнение: 16(1/2*x-2)(1/4*x^2+x+4)-2x(x-6)^2=24x^2.

\[- 128 = 72x\]

\[x = - \frac{128}{72} = - \frac{16}{9}\]

\[x = - 1\frac{7}{9}\]

\[Ответ:\ x = - 1\frac{7}{9}.\]