Решите уравнение: 25x^2+60x+36=0.

\[25x² + 60x + 36 = 0\ \ \]

\[a = 25,\ \ b = 60,\ \ c = 36\]

\[D = b^{2} - 4ac =\]

\[= 60^{2} - 4 \cdot 25 \cdot 36 =\]

\[= 3600 - 3600\]

\[x = \frac{- b \pm \sqrt{D}}{2a} = \frac{- 60 \pm \sqrt{0}}{2 \cdot 25} =\]

\[= - \frac{60}{50} = - \frac{6}{5} = - 1\frac{1}{5} = - 1,2.\]

\[Ответ:\ x = - 1,2.\]