Решите уравнение: (2x-1)(4x^2+2x+1)-8x(x^2+1)=3x+4.

\[(2x - 1)\left( 4x^{2} + 2x + 1 \right) - 8x\left( x^{2} + 1 \right) = 3x + 4\]

\[8x^{3} - 1 - 8x^{3} - 8x - 3x = 4\]

\[- 11x = 5\]

\[x = - \frac{5}{11}.\]