Решите уравнение: 2x(3x-2)-3*(x^2-4x)=3x(x-7)+2.

\[2x(3x - 2) - 3\left( x^{2} - 4x \right) =\]

\[= 3x(x - 7) + 2\]

\[6x^{2} - 4x - 3x^{2} + 12x =\]

\[= 3x^{2} - 21x + 2\]

\[8x + 21x = 2\]

\[29x = 2\]

\[x = \frac{2}{29}\]

\[Ответ:x = \frac{2}{29}.\]