Решите уравнение: 3/4+x=17/18.

\[\frac{3}{4} + x = \frac{17}{18}\]

\[x = \frac{17^{\backslash 2}}{18} - \frac{3^{\backslash 9}}{4}\]

\[x = \frac{34}{36} - \frac{27}{36}\]

\[x = \frac{7}{36}.\]