Решите уравнение 3x^2-2x-8=0.

\[3x^{2} - 2x - 8 = 0\]

\[D = 4 + 96 = 100\]

\[x_{1} = \frac{2 + 10}{6} = \frac{12}{6} = 2;\]

\[x_{2} = \frac{2 - 10}{6} = - \frac{4}{6} = - \frac{2}{3}.\]

\[Ответ:x = - \frac{2}{3};\ \ x = 2.\]