Решите уравнение: (4x-3)(4x+3)-(4x-1)^2=3x.

\[(4x - 3)(4x + 3) - (4x - 1)^{2} = 3x\]

\[16x^{2} - 9 - 16x^{2} + 8x - 1 = 3x\]

\[8x - 3x = 10\]

\[5x = 10\]

\[x = 2.\]