Решите уравнение: (8x+3)/7=(10x-1)/7.

\[\frac{8x + 3}{7} = \frac{10x - 1}{7}\ \ \ | \cdot 7\]

\[8x + 3 = 10x - 1\]

\[8x - 10x = - 1 - 3\]

\[- 2x = - 4\]

\[x = 2.\]