1. Решите уравнение: а) $$(1-3x)-(x + 2) = -8x+5$$; б) $$\frac{2x - 3}{3} = \frac{4x - 1}{5}$$.

Решение: а) $$(1-3x)-(x + 2) = -8x+5$$ $$1-3x-x-2 = -8x+5$$ $$-4x-1 = -8x+5$$ $$-4x+8x = 5+1$$ $$4x = 6$$ $$x = \frac{6}{4} = \frac{3}{2} = 1.5$$ б) $$\frac{2x - 3}{3} = \frac{4x - 1}{5}$$ $$5(2x-3) = 3(4x-1)$$ $$10x-15 = 12x-3$$ $$10x-12x = -3+15$$ $$-2x = 12$$ $$x = -6$$ Ответ: а) **x = 1.5** б) **x = -6**