\[\frac{x + 1}{x - 4} = \frac{3x + 1}{3x - 1}\]
\[\frac{x + 1^{\backslash 3x - 1}}{x - 4} - \frac{3x + 1^{\backslash x - 4}}{3x - 1} = 0\]
\[13x + 3 = 0\]
\[13x = - 3\]
\[x = - \frac{3}{13}\]
\[Ответ:\ x = - \frac{3}{13}.\]