\[(x + y)^{2} + (x - 1)^{2} = 0\]
\[\left\{ \begin{matrix}
x + y = 0 \\
x - 1 = 0 \\
\end{matrix} - \right.\ \text{\ \ \ \ \ \ }\]
\[\left\{ \begin{matrix}
y + 1 = 0 \\
x = 1\ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix}
y = - 1 \\
x = 1\ \ \ \ \\
\end{matrix} \right.\ \]
\[Ответ:(1;\ - 1).\]