Решите уравнение x^2=46

\[\ \ x² = 46\]

\[x = \pm \sqrt{46}\]

\[Ответ:x = \pm \sqrt{46}.\]

\[\ b \leq 0:\]

\[\frac{1}{3}b³\sqrt{9b^{2}} = \frac{1}{3} \cdot 3b³|b| = - b^{4}.\]