Решите уравнение: x^2(x+2)-(x+2)(x^2-x+3)=0.

\[x^{2}(x + 2) - (x + 2)\left( x^{2} - x + 3 \right) = 0\]

\[(x + 2)\left( x^{2} - x^{2} + x - 3 \right) = 0\]

\[(x + 2)(x - 3) = 0\]

\[x = - 2;\ \ x = 3.\]

\[Ответ:x = - 2;\ \ x = 3.\]