Вопрос:

338. Решите уравнение: 1) x - 4 \(\frac{5}{8}\) = 7 \(\frac{17}{32}\); 2) x + \(\frac{8}{9}\) = 1 \(\frac{7}{12}\); 3) 3 \(\frac{1}{6}\) - x = \(\frac{5}{18}\).

Смотреть решения всех заданий с листа

Ответ:

1) \(x - 4 \frac{5}{8} = 7 \frac{17}{32}\)

\(x = 7 \frac{17}{32} + 4 \frac{5}{8}\)

\(x = \frac{7 \cdot 32 + 17}{32} + \frac{4 \cdot 8 + 5}{8}\)

\(x = \frac{231}{32} + \frac{37}{8}\)

\(x = \frac{231}{32} + \frac{37 \cdot 4}{8 \cdot 4}\)

\(x = \frac{231}{32} + \frac{148}{32}\)

\(x = \frac{231 + 148}{32}\)

\(x = \frac{379}{32}\)

\(x = 11 \frac{27}{32}\)

Ответ: \(11 \frac{27}{32}\)

2) \(x + \frac{8}{9} = 1 \frac{7}{12}\)

\(x = 1 \frac{7}{12} - \frac{8}{9}\)

\(x = \frac{1 \cdot 12 + 7}{12} - \frac{8}{9}\)

\(x = \frac{19}{12} - \frac{8}{9}\)

\(x = \frac{19 \cdot 3}{12 \cdot 3} - \frac{8 \cdot 4}{9 \cdot 4}\)

\(x = \frac{57}{36} - \frac{32}{36}\)

\(x = \frac{57 - 32}{36}\)

\(x = \frac{25}{36}\)

Ответ: \(\frac{25}{36}\)

3) \(3 \frac{1}{6} - x = \frac{5}{18}\)

\(x = 3 \frac{1}{6} - \frac{5}{18}\)

\(x = \frac{3 \cdot 6 + 1}{6} - \frac{5}{18}\)

\(x = \frac{19}{6} - \frac{5}{18}\)

\(x = \frac{19 \cdot 3}{6 \cdot 3} - \frac{5}{18}\)

\(x = \frac{57}{18} - \frac{5}{18}\)

\(x = \frac{57 - 5}{18}\)

\(x = \frac{52}{18}\)

\(x = \frac{26}{9}\)

\(x = 2 \frac{8}{9}\)

Ответ: \(2 \frac{8}{9}\)

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