Решите уравнение: (x-2)(x+2)-x(x-3)=0.

\[(x - 2)(x + 2) - x(x - 3) = 0\]

\[x^{2} - 4 - x^{2} + 3x = 0\]

\[3x = 4\]

\[x = \frac{4}{3}\]

\[x = 1\frac{1}{3}.\]