Решите уравнение x+2x^2-15=0.

2x^2 + x - 15 = 0

D = 1^2 - 4 \(\cdot\) 2 \(\cdot\) (-15) = 1 + 120 = 121

x_1 = \(\frac{-1 - 11}{4}\) = -3, x_2 = \(\frac{-1 + 11}{4}\) = \(\frac{10}{4}\) = 2.5