Решите уравнение x/(x-4)-16/(x^2-4x)=0.

\[\frac{x}{x - 4} - \frac{16}{x^{2} - 4x} = 0\]

\[\frac{x}{x - 4} - \frac{16}{x(x - 4)} = 0\ \ \ \ | \cdot x(x - 4)\]

\[ОДЗ:\ x \neq 0;\ \ \ x \neq 4\]

\[x^{2} - 16 = 0\]

\[(x - 4)(x + 4) = 0\]

\[x - 4 = 0\ \ \ \ \ \ \ \ \ x = 4 - не\ подходит.\]

\[x + 4 = 0\ \ \ \ \ \ \ \ x = - 4.\]

\[Ответ:\ x = - 4.\]