Решите уравнение: a) (2x - 5)(5x + 4) - 10x² = 14; б) (4y + 3)(3y + 1) = (2y - 1)(6y + 5) – 1.

a) $$(2x - 5)(5x + 4) - 10x^2 = 14$$ $$10x^2 + 8x - 25x - 20 - 10x^2 = 14$$ $$-17x - 20 = 14$$ $$-17x = 34$$ $$x = -2$$ б) $$(4y + 3)(3y + 1) = (2y - 1)(6y + 5) - 1$$ $$12y^2 + 4y + 9y + 3 = 12y^2 + 10y - 6y - 5 - 1$$ $$12y^2 + 13y + 3 = 12y^2 + 4y - 6$$ $$13y - 4y = -6 - 3$$ $$9y = -9$$ $$y = -1$$ **Ответы:** a) $$\mathbf{x = -2}$$ б) $$\mathbf{y = -1}$$