5. Решите уравнение: a) (3x - 2)(3x + 2) - (3x - 8)² = 14x; б) 25x² - 36 = 0.

а) \((3x - 2)(3x + 2) - (3x - 8)^2 = 14x\) \(9x^2 - 4 - (9x^2 - 48x + 64) = 14x\) \(9x^2 - 4 - 9x^2 + 48x - 64 = 14x\) \(48x - 68 = 14x\) \(34x = 68\) \(x = 2\) Ответ: **x = 2** б) \(25x^2 - 36 = 0\) \(25x^2 = 36\) \(x^2 = \frac{36}{25}\) \(x = \pm \sqrt{\frac{36}{25}}\ \(x = \pm \frac{6}{5}\) Ответ: **x = ±6/5**