Контрольные задания > 2.252 Решите уравнение: a) $1-y = \frac{7}{24}+\frac{1}{4}$; б) $1+m = \frac{3}{5}+\frac{6}{15}$; в) $l+3\frac{5}{6}=7\frac{1}{6}-2\frac{2}{3}$.
Вопрос:

2.252 Решите уравнение: a) $$1-y = \frac{7}{24}+\frac{1}{4}$$; б) $$1+m = \frac{3}{5}+\frac{6}{15}$$; в) $$l+3\frac{5}{6}=7\frac{1}{6}-2\frac{2}{3}$$.

Смотреть решения всех заданий с листа

Ответ:

  1. a) $$1-y = \frac{7}{24}+\frac{1}{4}$$
    $$1-y = \frac{7}{24}+\frac{1\cdot6}{4\cdot6}$$
    $$1-y = \frac{7}{24}+\frac{6}{24}$$
    $$1-y = \frac{7+6}{24}$$
    $$1-y = \frac{13}{24}$$
    $$y = 1-\frac{13}{24}$$
    $$y = \frac{24}{24}-\frac{13}{24}$$
    $$y = \frac{24-13}{24}$$
    $$y = \frac{11}{24}$$
    Ответ: $$y=\frac{11}{24}$$
  2. б) $$1+m = \frac{3}{5}+\frac{6}{15}$$
    $$1+m = \frac{3\cdot3}{5\cdot3}+\frac{6}{15}$$
    $$1+m = \frac{9}{15}+\frac{6}{15}$$
    $$1+m = \frac{9+6}{15}$$
    $$1+m = \frac{15}{15}$$
    $$1+m = 1$$
    $$m = 1-1$$
    $$m = 0$$
    Ответ: $$m=0$$
  3. в) $$l+3\frac{5}{6}=7\frac{1}{6}-2\frac{2}{3}$$
    $$l+3\frac{5}{6}=7\frac{1}{6}-2\frac{2\cdot2}{3\cdot2}$$
    $$l+3\frac{5}{6}=7\frac{1}{6}-2\frac{4}{6}$$
    $$l+3\frac{5}{6}=(7-2)+(\frac{1}{6}-\frac{4}{6})$$
    $$l+3\frac{5}{6}=5-\frac{3}{6}$$
    $$l+3\frac{5}{6}=5-\frac{1}{2}$$
    $$l+3\frac{5}{6}=4\frac{1}{2}$$
    $$l = 4\frac{1}{2}-3\frac{5}{6}$$
    $$l = 4\frac{1\cdot3}{2\cdot3}-3\frac{5}{6}$$
    $$l = 4\frac{3}{6}-3\frac{5}{6}$$
    $$l = 3\frac{3+6}{6}-3\frac{5}{6}$$
    $$l = 3\frac{9}{6}-3\frac{5}{6}$$
    $$l = (3-3) + (\frac{9}{6}-\frac{5}{6})$$
    $$l = \frac{9-5}{6}$$
    $$l = \frac{4}{6}$$
    $$l = \frac{2}{3}$$
    Ответ: $$l=\frac{2}{3}$$
ГДЗ по фото 📸
Подать жалобу Правообладателю

Похожие