Решите уравнения: 1) 12 - 2(x + 3) = 26; 2) -5(3x + 1) - 11 = -16; 3) x - 32 = (x + 8) * (-7).

Решение:

1. \( 12 - 2(x + 3) = 26 \)

\( 12 - 2x - 6 = 26 \)
\( 6 - 2x = 26 \)
\( -2x = 26 - 6 \)
\( -2x = 20 \)
\( x = \frac{20}{-2} \)
\( x = -10 \)

2. \( -5(3x + 1) - 11 = -16 \)

\( -15x - 5 - 11 = -16 \)
\( -15x - 16 = -16 \)
\( -15x = -16 + 16 \)
\( -15x = 0 \)
\( x = \frac{0}{-15} \)
\( x = 0 \)

3. \( x - 32 = (x + 8) \cdot (-7) \)

\( x - 32 = -7x - 56 \)
\( x + 7x = -56 + 32 \)
\( 8x = -24 \)
\( x = \frac{-24}{8} \)
\( x = -3 \)

Ответ: 1) x = -10; 2) x = 0; 3) x = -3.