3.
a) х + 2$$\frac{3}{15}$$ = 5$$\frac{9}{20}$$
x + $$\frac{33}{15}$$ = $$\frac{109}{20}$$
x = $$\frac{109}{20}$$ - $$\frac{33}{15}$$
x = $$\frac{109 \cdot 3}{20 \cdot 3}$$ - $$\frac{33 \cdot 4}{15 \cdot 4}$$
x = $$\frac{327}{60}$$ - $$\frac{132}{60}$$
x = $$\frac{195}{60}$$ = $$\frac{13}{4}$$ = 3$$\frac{1}{4}$$
Ответ: 3$$\frac{1}{4}$$
б) у$$\cdot$$3$$\frac{4}{5}$$ = 2$$\frac{1}{9}$$
у$$\cdot$$\frac{19}{5}$$ = $$\frac{19}{9}$$
y = $$\frac{19}{9}$$ : $$\frac{19}{5}$$
y = $$\frac{19}{9}$$\cdot$$\frac{5}{19}$$ = $$\frac{5}{9}$$
Ответ: $$\frac{5}{9}$$