\(7\frac{2}{3}\cdot\left(-\frac{9}{11}\right):4,6-(-2,75):3\frac{3}{4} = \frac{23}{3}\cdot\left(-\frac{9}{11}\right):\frac{46}{10}- \left(-\frac{275}{100}\right):\frac{15}{4} = \frac{23}{3}\cdot\left(-\frac{9}{11}\right)\cdot\frac{10}{46}- \left(-\frac{11}{4}\right):\frac{15}{4} = \left(-\frac{23\cdot 9\cdot 10}{3\cdot 11\cdot 46}\right) - \left(-\frac{11}{4}\right)\cdot\frac{4}{15} = \left(-\frac{23\cdot (3\cdot 3)\cdot (2\cdot 5)}{(3\cdot 11)\cdot (2\cdot 23)}\right) - \left(-\frac{11}{15}\right) = \left(-\frac{3\cdot 5}{11}\right) + \frac{11}{15} = -\frac{15}{11} + \frac{11}{15} = \frac{-15\cdot 15 + 11\cdot 11}{165} = \frac{-225+121}{165} = \frac{-104}{165}\)
Ответ: -\( \frac{104}{165} \)