S(t) = 12t^4 - 6t^3 + 2t^2 - 9, v(2) = ?

The velocity function v(t) is the derivative of the position function S(t).

v(t) = dS/dt = d/dt (12t^4 - 6t^3 + 2t^2 - 9) = 48t^3 - 18t^2 + 4t.

Now, substitute t=2 into the velocity function: v(2) = 48(2)^3 - 18(2)^2 + 4(2) = 48(8) - 18(4) + 8 = 384 - 72 + 8 = 320.