Вопрос:

Select all the squares in order of least to greatest

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Ответ:

Let's solve the expressions: 1. $$\frac{11}{14} \approx 0.7857$$ 2. $$\sqrt{9} = 3$$ 3. $$\sum_{i=2}^{6} i = 2 + 3 + 4 + 5 + 6 = 20$$ 4. $$\log_4(14)$$. Since $$4^1 = 4$$ and $$4^2 = 16$$, $$\log_4(14)$$ is between 1 and 2. Let's estimate it to be approximately 1.9. 5. $$\int_{3}^{9} x dx = \frac{x^2}{2} \Big|_3^9 = \frac{9^2}{2} - \frac{3^2}{2} = \frac{81}{2} - \frac{9}{2} = \frac{72}{2} = 36$$ 6. $$5! = 5 \times 4 \times 3 \times 2 \times 1 = 120$$ 7. $$e^6 \approx 403.43$$ 8. $$\frac{2\pi}{2} = \pi \approx 3.14$$ Ordering these from least to greatest: $$\frac{11}{14} \approx 0.7857$$ $$\sqrt{9} = 3$$ $$\frac{2\pi}{2} = \pi \approx 3.14$$ $$\log_4(14) \approx 1.9$$ $$\sum_{i=2}^{6} i = 20$$ $$\int_{3}^{9} x dx = 36$$ $$5! = 120$$ $$e^6 \approx 403.43$$ Final order: 1. $$\frac{11}{14}$$ (0.7857) 2. $$\sqrt{9}$$ (3) 3. $$\frac{2\pi}{2}$$ (3.14) 4. $$\log_4(14)$$ (1.9) 5. $$\sum_{i=2}^{6} i$$ (20) 6. $$\int_{3}^{9} x dx$$ (36) 7. $$5!$$ (120) 8. $$e^6$$ (403.43)
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