Simplify the expression $$\frac{d^2 d^3 d^{-4}}{d^{-5}}$$ and evaluate it for $$d=27$$.

Simplify the expression:

1. Combine terms in the numerator: $$d^{2+3-4} = d^1$$.
2. Divide by the denominator: $$\frac{d^1}{d^{-5}} = d^{1 - (-5)} = d^{1+5} = d^6$$.
3. Evaluate for $$d=27$$: $$27^6 = (3^3)^6 = 3^{18}$$.

The simplified expression is $$d^6$$, and for $$d=27$$, the value is $$3^{18}$$.