Вопрос:

Simplify the following algebraic expressions: 1) 4a² - b² + 12a + 6b 2) 64x² - 16xy + y² - 9

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Ответ:

Solution:

  • 1) 4a² - b² + 12a + 6b
    This expression can be factored by grouping. We can rearrange the terms to group similar variables together: (4a² + 12a) + (-b² + 6b).
    Factor out the common terms from each group: 4a(a + 3) - b(b - 6).
    At this point, it does not appear to factor further into a simple form without additional information or context suggesting a specific type of factorization (like a difference of squares or a perfect square trinomial applied to a portion of the expression). If this were intended to be a perfect square, it would likely have a structure like (2a ± b)². However, the terms +12a and +6b do not fit this pattern directly.
  • 2) 64x² - 16xy + y² - 9
    This expression can be recognized as a combination of a perfect square trinomial and a difference of squares.
    First, group the terms that form a perfect square: (64x² - 16xy + y²). This is the expansion of (8x - y)².
    So, the expression becomes (8x - y)² - 9.
    This is now in the form of a difference of squares, a² - b², where a = (8x - y) and b = 3.
    The difference of squares factors as (a - b)(a + b).
    Substituting our values: ((8x - y) - 3)((8x - y) + 3).
    Therefore, the factored form is (8x - y - 3)(8x - y + 3).

Final Answer:

1) 4a² - b² + 12a + 6b (Cannot be easily factored into a simple form)

2) (8x - y - 3)(8x - y + 3)

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