Выполним действия по порядку.
1) $$\frac{11}{14} - \frac{1}{6} = \frac{11 \cdot 3}{14 \cdot 3} - \frac{1 \cdot 7}{6 \cdot 7} = \frac{33}{42} - \frac{7}{42} = \frac{33-7}{42} = \frac{26}{42} = \frac{13}{21}$$
2) $$\frac{7}{39} \cdot \frac{13}{21} = \frac{7 \cdot 13}{39 \cdot 21} = \frac{7 \cdot 13}{3 \cdot 13 \cdot 3 \cdot 7} = \frac{1}{3 \cdot 3} = \frac{1}{9}$$
3) $$\frac{15}{32} : \frac{5}{8} = \frac{15}{32} \cdot \frac{8}{5} = \frac{15 \cdot 8}{32 \cdot 5} = \frac{3 \cdot 5 \cdot 8}{4 \cdot 8 \cdot 5} = \frac{3}{4}$$
4) $$\frac{3}{4} + \frac{3}{20} = \frac{3 \cdot 5}{4 \cdot 5} + \frac{3}{20} = \frac{15}{20} + \frac{3}{20} = \frac{15+3}{20} = \frac{18}{20} = \frac{9}{10}$$
Ответ: $$\frac{1}{9}; \frac{9}{10}$$