a) 3 + \(\frac{2}{5}\) = 3\(\frac{2}{5}\)
б) 29 + \(\frac{11}{15}\) = 29\(\frac{11}{15}\)
a) 12\(\frac{3}{20}\) = 12 + \(\frac{3}{20}\)
б) \(\frac{41}{43}\) = 0 + \(\frac{41}{43}\)
в) 7\(\frac{6}{19}\) = 7 + \(\frac{6}{19}\)
a) \(\frac{23}{5}\); 23 : 5 = 4 (ост. 3), поэтому \(\frac{23}{5}\) = 4\(\frac{3}{5}\)
б) \(\frac{40}{7}\); 40 : 7 = 5 (ост. 5), поэтому \(\frac{40}{7}\) = 5\(\frac{5}{7}\)
в) \(\frac{95}{9}\); 95 : 9 = 10 (ост. 5), поэтому \(\frac{95}{9}\) = 10\(\frac{5}{9}\)
a) 3\(\frac{2}{9}\) = \(\frac{9 \cdot 3 + 2}{9}\) = \(\frac{27 + 2}{9}\) = \(\frac{29}{9}\)
б) 4\(\frac{3}{11}\) = \(\frac{11 \cdot 4 + 3}{11}\) = \(\frac{44 + 3}{11}\) = \(\frac{47}{11}\)
в) 1\(\frac{15}{29}\) = \(\frac{29 \cdot 1 + 15}{29}\) = \(\frac{29 + 15}{29}\) = \(\frac{44}{29}\)
г) 5\(\frac{11}{12}\) = \(\frac{12 \cdot 5 + 11}{12}\) = \(\frac{60 + 11}{12}\) = \(\frac{71}{12}\)
a) 4 м 3 см = 4 м + 3 см = 4 м + \(\frac{3}{100}\) м = 4\(\frac{3}{100}\) м
б) 15 м 36 см = 15 м + 36 см = 15 м + \(\frac{36}{100}\) м = 15\(\frac{36}{100}\) м = 15.36 м
в) 2 км 5 дм = 2000 м + 5 дм = 2000 м + \(\frac{5}{10}\) м = 2000.5 м
a) 3 кг 17 г = 3 кг + 17 г = 3 кг + \(\frac{17}{1000}\) кг = 3.017 кг
б) 48 кг 239 г = 48 кг + 239 г = 48 кг + \(\frac{239}{1000}\) кг = 48.239 кг
Ответ: смотри выше