3) Сократите: \frac{9*16}{8*27}; \frac{8*28}{35*12}; \frac{2*3*5}{4*9*25}

Сократим каждую дробь:

• \(\frac{9 \cdot 16}{8 \cdot 27} = \frac{9 \div 9 \cdot 16}{8 \cdot 27 \div 9} = \frac{1 \cdot 16}{8 \cdot 3} = \frac{16}{24} = \frac{16 \div 8}{24 \div 8} = \frac{2}{3}\)
• \(\frac{8 \cdot 28}{35 \cdot 12} = \frac{8 \cdot 28 \div 4}{35 \cdot 12 \div 4} = \frac{8 \cdot 7}{35 \cdot 3} = \frac{8 \cdot 7}{35 \div 7 \cdot 3} = \frac{8 \cdot 7}{5 \cdot 3} = \frac{56}{15}\)
• \(\frac{2 \cdot 3 \cdot 5}{4 \cdot 9 \cdot 25} = \frac{2 \cdot 3 \cdot 5}{2 \cdot 2 \cdot 3 \cdot 3 \cdot 5 \cdot 5} = \frac{1}{2 \cdot 3 \cdot 5} = \frac{1}{30}\)

Ответ: \(\frac{2}{3}, \frac{56}{15}, \frac{1}{30}\)