Сократите дробь: (b^2-b-6)/(9b+18).

Ответ:

\[\frac{b^{2} - b - 6}{9b + 18} = \frac{(b - 3)(b + 2)}{9(b + 2)} =\]

\[= \frac{b - 3}{9}\]

\[b^{2} - b - 6 = 0\]

\[b_{1} + b_{2} = 1;\ \ \ b_{1} \cdot b_{2} = - 6\]

\[b_{1} = 3;\ \ \ b_{2} = - 2.\]