Сократите дробь: (b^3-27)/(5b^2-16b+3).

Ответ:

\[5b^{2} - 16b + 3 = 0\]

\[b_{1} + b_{2} = \frac{16}{5}\]

\[b_{1} \cdot b_{2} = \frac{3}{5}\]

\[\Longrightarrow b_{1} = 3;\ b_{2} = \frac{1}{5}.\]

\[5b^{2} - 16b + 3 =\]

\[= 5 \cdot (b - 3)\left( b - \frac{1}{5} \right) =\]

\[= (b - 3)(5b - 1).\]