Сократите дробь: (c^2+c-6)/(7c+21).

Ответ:

\[\frac{c^{2} + c - 6}{7c + 21} = \frac{(c - 2)(c + 3)}{7 \cdot (c + 3)} =\]

\[= \frac{c - 2}{7}\]

\[c^{2} + c - 6 = (c - 2)(c + 3)\]

\[c_{1} + c_{2} = - 1;\ \ c_{1} \cdot c_{2} = - 6\]

\[c_{1} = - 3;\ \ c_{2} = 2.\]