Сократите дробь: В) $$\frac{2ay^3}{-4a^2b}$$

$$\frac{2ay^3}{-4a^2b} = \frac{2}{-4} \cdot \frac{a}{a^2} \cdot \frac{y^3}{1} \cdot \frac{1}{b} = -\frac{1}{2} \cdot \frac{1}{a} \cdot y^3 \cdot \frac{1}{b} = -\frac{y^3}{2ab}$$