Вопрос:

Сократите дроби: а) \(\frac{3ab^2}{4a^2}\); б) \(\frac{m^2n}{b^2m^2n^2}\); в) \(\frac{5x-15y}{x^2-9y^2}\); г) \(\frac{3a-6b}{3b}\); д) \(\frac{6ac-18c}{(a-3)^2}\); е) \(\frac{3a-6b}{3b}\); ж) \(\frac{30a^2b}{30a^2-6ab^2}\); з) \(\frac{y^2-9}{y^2-6y+9}\).

Ответ:

а) \(\frac{3ab^2}{4a^2}=\frac{3b^2}{4a}\).

б) \(\frac{m^2n}{b^2m^2n^2}=\frac{1}{b^2n}\).

в) \(\frac{5x-15y}{x^2-9y^2}=\frac{5(x-3y)}{(x-3y)(x+3y)}=\frac{5}{x+3y}\).

г) \(\frac{3a-6b}{3b}=\frac{3(a-2b)}{3b}=\frac{a-2b}{b}\).

д) \(\frac{6ac-18c}{(a-3)^2}=\frac{6c(a-3)}{(a-3)^2}=\frac{6c}{a-3}\).

е) \(\frac{3a-6b}{3b}=\frac{a-2b}{b}\).

ж) \(\frac{30a^2b}{30a^2-6ab^2}=\frac{30a^2b}{6a(5a-b^2)}=\frac{5ab}{5a-b^2}\).

з) \(\frac{y^2-9}{y^2-6y+9}=\frac{(y-3)(y+3)}{(y-3)^2}=\frac{y+3}{y-3}\).

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