Solve for 'y' in the given equations.

Solution:

The problem presents two equations:

1. The first equation is written as \( y = 3k + 8 \). This equation expresses \( y \) in terms of \( k \).
2. The second equation, enclosed in a box, is written as \( y = 2k \). This equation also expresses \( y \) in terms of \( k \).

To solve for \( y \), we can set the two expressions for \( y \) equal to each other, assuming that these two equations must hold simultaneously for some value of \( k \) for \( y \) to have a consistent value.

1. Set the expressions for \( y \) equal: \( 3k + 8 = 2k \)
2. Solve for \( k \):
• Subtract \( 2k \) from both sides: \( 3k - 2k + 8 = 0 \) \( k + 8 = 0 \)
• Subtract \( 8 \) from both sides: \( k = -8 \)
3. Substitute the value of \( k \) back into either equation to find \( y \). Using the second equation \( y = 2k \):
• \( y = 2 \times (-8) \)
• \( y = -16 \)

Alternatively, using the first equation \( y = 3k + 8 \):

1. \( y = 3 \times (-8) + 8 \)
2. \( y = -24 + 8 \)
3. \( y = -16 \)

Both equations yield the same value for \( y \) when \( k = -8 \).

Ответ: y = -16.