Solution:
We are asked to solve the equation \(\sqrt{9/6} = 8 - 5 \sqrt{x-1}\).
- Simplify the left side: \(\sqrt{9/6} = \sqrt{3/2} = \frac{\sqrt{3}}{\sqrt{2}} = \frac{\sqrt{6}}{2}\).
- Isolate the square root term: \(\frac{\sqrt{6}}{2} = 8 - 5 \sqrt{x-1}\)
\(5 \sqrt{x-1} = 8 - \frac{\sqrt{6}}{2}\)
\(5 \sqrt{x-1} = \frac{16 - \sqrt{6}}{2}\)
\(\sqrt{x-1} = \frac{16 - \sqrt{6}}{10}\). - Square both sides: \(x-1 = \left(\frac{16 - \sqrt{6}}{10}\right)^2\)
\(x-1 = \frac{16^2 - 2 * 16 * \sqrt{6} + (\sqrt{6})^2}{100}\)
\(x-1 = \frac{256 - 32\sqrt{6} + 6}{100}\)
\(x-1 = \frac{262 - 32\sqrt{6}}{100}\)
\(x-1 = \frac{131 - 16\sqrt{6}}{50}\). - Solve for x: \(x = 1 + \frac{131 - 16\sqrt{6}}{50}\)
\(x = \frac{50 + 131 - 16\sqrt{6}}{50}\)
\(x = \frac{181 - 16\sqrt{6}}{50}\).
Answer: \(x = \frac{181 - 16\sqrt{6}}{50}\)