Problem 1:
The problem appears to be calculating fractions. Based on the visual cues, it seems to involve subtraction and possibly addition of fractions.
Visual representation suggests:
Let's solve each part:
Part 1:
$$ \frac{3}{4} - \frac{2}{15} $$
Find a common denominator for 4 and 15, which is 60.
$$ \frac{3 \times 15}{4 \times 15} - \frac{2 \times 4}{15 \times 4} = \frac{45}{60} - \frac{8}{60} = \frac{37}{60} $$
Part 2:
$$ \frac{2}{3} + \frac{1}{6} $$
Find a common denominator for 3 and 6, which is 6.
$$ \frac{2 \times 2}{3 \times 2} + \frac{1}{6} = \frac{4}{6} + \frac{1}{6} = \frac{5}{6} $$
Part 3:
$$ \frac{7}{15} + \frac{2}{5} $$
Find a common denominator for 15 and 5, which is 15.
$$ \frac{7}{15} + \frac{2 \times 3}{5 \times 3} = \frac{7}{15} + \frac{6}{15} = \frac{13}{15} $$
Part 4:
$$ \frac{5}{35} $$
This fraction can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 5.
$$ \frac{5 \div 5}{35 \div 5} = \frac{1}{7} $$
Problem 2:
The image also shows what looks like a circled number '4'. It's unclear if this is a problem number or part of a calculation.
There is also a handwritten note that looks like '37-27=27-2'. This is arithmetically incorrect. If it's meant to be $$37 - 27 = 10$$ and $$27 - 2 = 25$$. The equality does not hold.
Summary of calculations:
Note: Some parts of the image are unclear, and the handwritten equation '37-27=27-2' appears to be erroneous.