Solve the fraction problems.

Решение:

Выполним вычисления для каждого примера:

1. \( \frac{1}{3} - \frac{1}{6} = \frac{2}{6} - \frac{1}{6} = \frac{1}{6} \)
2. \( \frac{3}{20} + \frac{3}{4} = \frac{3}{20} + \frac{15}{20} = \frac{18}{20} = \frac{9}{10} \)
3. \( \frac{7}{9} - \frac{2}{3} = \frac{7}{9} - \frac{6}{9} = \frac{1}{9} \)
4. \( \frac{1}{4} + \frac{1}{5} = \frac{5}{20} + \frac{4}{20} = \frac{9}{20} \)
5. \( \frac{2}{5} + \frac{4}{15} = \frac{6}{15} + \frac{4}{15} = \frac{10}{15} = \frac{2}{3} \)
6. \( \frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12} \)
7. \( \frac{2}{3} - \frac{2}{5} = \frac{10}{15} - \frac{6}{15} = \frac{4}{15} \)
8. \( \frac{1}{5} - \frac{1}{6} = \frac{6}{30} - \frac{5}{30} = \frac{1}{30} \)
9. \( \frac{1}{2} + \frac{1}{4} = \frac{2}{4} + \frac{1}{4} = \frac{3}{4} \)
10. \( \frac{7}{6} - 1 = \frac{7}{6} - \frac{6}{6} = \frac{1}{6} \)
11. \( \frac{1}{2} + \frac{2}{7} = \frac{7}{14} + \frac{4}{14} = \frac{11}{14} \)
12. \( \frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6} \)
13. \( \frac{3}{4} + \frac{1}{8} = \frac{6}{8} + \frac{1}{8} = \frac{7}{8} \)
14. \( \frac{5}{6} - \frac{7}{12} = \frac{10}{12} - \frac{7}{12} = \frac{3}{12} = \frac{1}{4} \)
15. \( \frac{2}{5} + \frac{3}{10} = \frac{4}{10} + \frac{3}{10} = \frac{7}{10} \)
16. \( \frac{8}{9} + \frac{7}{54} = \frac{48}{54} + \frac{7}{54} = \frac{55}{54} \)
17. \( \frac{5}{6} - \frac{17}{21} = \frac{35}{42} - \frac{34}{42} = \frac{1}{42} \)
18. \( \frac{3}{16} + \frac{1}{24} = \frac{9}{48} + \frac{2}{48} = \frac{11}{48} \)
19. \( \frac{5}{6} - \frac{22}{27} = \frac{45}{54} - \frac{44}{54} = \frac{1}{54} \)
20. \( \frac{7}{25} - \frac{4}{15} = \frac{21}{75} - \frac{20}{75} = \frac{1}{75} \)
21. \( \frac{3}{10} + \frac{1}{6} = \frac{9}{30} + \frac{5}{30} = \frac{14}{30} = \frac{7}{15} \)
22. \( \frac{2}{5} - \frac{11}{30} = \frac{12}{30} - \frac{11}{30} = \frac{1}{30} \)
23. \( \frac{3}{8} + \frac{7}{20} = \frac{15}{40} + \frac{14}{40} = \frac{29}{40} \)
24. \( \frac{1}{6} - \frac{1}{7} = \frac{7}{42} - \frac{6}{42} = \frac{1}{42} \)
25. \( \frac{5}{9} + \frac{7}{15} = \frac{25}{45} + \frac{21}{45} = \frac{46}{45} \)
26. \( \frac{3}{8} + \frac{19}{56} = \frac{21}{56} + \ \frac{19}{56} = \frac{40}{56} = \frac{5}{7} \)
27. \( \frac{19}{45} - \frac{7}{18} = \frac{38}{90} - \frac{35}{90} = \frac{3}{90} = \frac{1}{30} \)
28. \( \frac{1}{4} - \frac{1}{8} = \frac{2}{8} - \frac{1}{8} = \frac{1}{8} \)
29. \( \frac{11}{10} + \frac{8}{7} = \frac{77}{70} + \frac{80}{70} = \frac{157}{70} \)

Ответ: \(\begin{tabular}{|c|c|}\) ablehead{} \(\text{№}\) & \(\text{Ответ}\) \ \(\text{1.}\) & \(\frac{1}{6}\) \ \(\text{2.}\) & \(\frac{9}{10}\) \ \(\text{3.}\) & \(\frac{1}{9}\) \ \(\text{4.}\) & \(\frac{9}{20}\) \ \(\text{5.}\) & \(\frac{2}{3}\) \ \(\text{6.}\) & \(\frac{7}{12}\) \ \(\text{7.}\) & \(\frac{4}{15}\) \ \(\text{8.}\) & \(\frac{1}{30}\) \ \(\text{9.}\) & \(\frac{3}{4}\) \ \(\text{10.}\) & \(\frac{1}{6}\) \ \(\text{11.}\) & \(\frac{11}{14}\) \ \(\text{12.}\) & \(\frac{1}{6}\) \ \(\text{13.}\) & \(\frac{7}{8}\) \ \(\text{14.}\) & \(\frac{1}{4}\) \ \(\text{15.}\) & \(\frac{7}{10}\) \ \(\text{16.}\) & \(\frac{55}{54}\) \ \(\text{17.}\) & \(\frac{1}{42}\) \ \(\text{18.}\) & \(\frac{11}{48}\) \ \(\text{19.}\) & \(\frac{1}{54}\) \ \(\text{20.}\) & \(\frac{1}{75}\) \ \(\text{21.}\) & \(\frac{7}{15}\) \ \(\text{22.}\) & \(\frac{1}{30}\) \ \(\text{23.}\) & \(\frac{29}{40}\) \ \(\text{24.}\) & \(\frac{1}{42}\) \ \(\text{25.}\) & \(\frac{46}{45}\) \ \(\text{26.}\) & \(\frac{5}{7}\) \ \(\text{27.}\) & \(\frac{1}{30}\) \ \(\text{28.}\) & \(\frac{1}{8}\) \ \(\text{29.}\) & \(\frac{157}{70}\) \ \(\text{30.}\) & \(\frac{11}{30}\) \ \(\text{}\) & \(\text{}\) abular}