Solve the system of equations: { 3x + 4y - 11 = 0, 5x - 2y - 14 = 0 }

Multiply the second equation by 2 to eliminate y:

3x + 4y - 11 = 0

10x - 4y - 28 = 0

Add the two equations:

13x - 39 = 0

13x = 39

x = 3

Substitute x = 3 into the first equation:

3(3) + 4y - 11 = 0

9 + 4y - 11 = 0

4y - 2 = 0

4y = 2

y = 1/2

The solution is x = 3, y = 1/2.