System of Equations:
- Equation 1: \( 5x - 2y = -16 \)
- Equation 2: \( 8x - 7y = 1 \)
Method: We will use the elimination method to solve this system of equations. We'll multiply each equation by a constant so that the coefficients of one variable are opposites.
Step-by-step solution:
- Step 1: Multiply Equation 1 by 7 and Equation 2 by 2
To eliminate y, multiply the first equation by 7 and the second equation by 2:
Equation 1 multiplied by 7: \( 7(5x - 2y) = 7(-16) \) which results in \( 35x - 14y = -112 \).
Equation 2 multiplied by 2: \( 2(8x - 7y) = 2(1) \) which results in \( 16x - 14y = 2 \). - Step 2: Subtract the modified Equation 2 from the modified Equation 1
Subtract the second modified equation from the first modified equation:
\( (35x - 14y) - (16x - 14y) = -112 - 2 \)
\( 35x - 14y - 16x + 14y = -114 \)
\( 19x = -114 \) - Step 3: Solve for x
Divide by 19: \( x = -114 / 19 \)
\( x = -6 \) - Step 4: Substitute x back into Equation 1 to find y
Substitute \( x = -6 \) into the original Equation 1: \( 5x - 2y = -16 \)
\( 5(-6) - 2y = -16 \)
\( -30 - 2y = -16 \) - Step 5: Solve for y
Add 30 to both sides: \( -2y = -16 + 30 \)
\( -2y = 14 \)
Divide by -2: \( y = -7 \)
Answer: x = -6, y = -7