Here is the solution to the system:
Given system:
1. \( x + xy + y = -3 \)
2. \( x^2 + y^2 = 5 \)
Step 1: Solve equation (1) for \( x \):
\[ x + xy + y = -3 \]
\[ x(1 + y) + y = -3 \]
\[ x = \frac{-3 - y}{1 + y}, \text{ when } y
eq -1. \]
Step 2: Substitute this \( x \) into equation (2):
\[ \left(\frac{-3 - y}{1 + y}\right)^2 + y^2 = 5 \]
Simplify and solve for \( y \). Then substitute back to find \( x \).
Final solutions:
- \( x_1 = -2, y_1 = 1 \)
- \( x_2 = 1, y_2 = -2 \).