Solve the system of equations: {7x - 5y - 4 = 0, 10y = 14x + 3.

Solving the system of equations:

First, let’s rewrite the equations to make them easier to work with: 1) 7x - 5y - 4 = 0 2) 10y = 14x + 3 From equation (1), we can express \(y\) in terms of \(x\): 7x - 5y - 4 = 0 \(\Rightarrow\) 5y = 7x - 4 \(\Rightarrow\) y = \(\frac{7x - 4}{5}\) Now, substitute this expression for \(y\) into equation (2): 10(\(\frac{7x - 4}{5}\)) = 14x + 3 Simplify: 2(7x - 4) = 14x + 3 \(\Rightarrow\) 14x - 8 = 14x + 3 Subtract \(14x\) from both sides: -8 = 3 Since -8 \(
eq\) 3, there is no solution to this system of equations because it leads to a contradiction.

Answer: No solution.