Solve the system of equations: x - 2y = -8, x - 3y = -8

Solution using elimination:

1. Subtract the second equation from the first equation to eliminate x: \( (x - 2y) - (x - 3y) = -8 - (-8) \).
2. Simplify and solve for y: \( x - 2y - x + 3y = -8 + 8 \) => \( y = 0 \).
3. Substitute the value of y back into either original equation. Using the first equation: \( x - 2(0) = -8 \).
4. Solve for x: \( x - 0 = -8 \) => \( x = -8 \).

Answer: x = -8, y = 0