The provided image contains a chemistry problem related to the formation of an ionic bond between sodium (Na) and chlorine (Cl). The question asks to fill in the blanks regarding the number of electrons transferred and the charges of the resulting ions. The image shows the electron configurations of Na (2, 8, 1) and Cl (2, 8, 7), and the resulting ions Na+ (2, 8) and Cl- (2, 8, 8). The diagram also visually represents the transfer of one electron from Na to Cl. The text prompts are: 1. Количество электронов, которые отдаёт на образование связи атом натрия: [dropdown showing '1'] 2. Количество электронов, которые принимает при образовании связи атом хлора: [dropdown showing '1'] 3. Заряд иона натрия: [dropdown 'Выбери ответ'] 4. Заряд иона хлора: [dropdown 'Выбери ответ'] Based on the provided diagram and chemical principles: - Sodium (Na) has 1 valence electron, which it readily loses to achieve a stable electron configuration. This electron is transferred to chlorine. - Chlorine (Cl) has 7 valence electrons and needs one more electron to achieve a stable octet. It accepts the electron from sodium. - When sodium loses one electron, it forms a cation with a +1 charge (Na+). - When chlorine gains one electron, it forms an anion with a -1 charge (Cl-). Therefore, the correct answers should reflect these facts. The dropdowns in the image already suggest '1' for the number of electrons transferred by both Na and Cl. The task is to select the correct charges for the ions.

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