The provided image contains mathematical expressions and a word problem. Please extract and analyze these components.

The image contains several mathematical expressions and a word problem related to calculating mass.

Mathematical Expressions Observed:

• Variations of 'b' with fractional values:
• b = \(\frac{1}{5}\)
• b = \(\frac{5}{12}\)
• b = \(\frac{6}{5}\)
• b = \(\frac{84}{25}\)
• b = 0
• A problem statement involving mass and volume:
• Масса 1 м³ древесины \(\frac{14}{25}\) т. (Mass of 1 m³ of wood is 14/25 tons.)
• Найдите массу \(\frac{3}{4}\) м³ и \(\frac{5}{7}\) м³ древесины. (Find the mass of 3/4 m³ and 5/7 m³ of wood.)

Analysis of the Word Problem:

The problem provides the density of wood in terms of mass per unit volume (14/25 tons per 1 m³). It then asks to calculate the mass for two different volumes of wood: 3/4 m³ and 5/7 m³.

To solve this, we would use the formula: Mass = Density × Volume.

Calculations:

1. Mass for 3/4 m³:
   Mass = \(\frac{14}{25} \text{ т/м³}\) \(\times\) \(\frac{3}{4} \text{ м³}\)
Mass = \(\frac{14 \times 3}{25 \times 4}\) \(\text{ т}\)
Mass = \(\frac{42}{100}\) \(\text{ т}\)
Mass = \(\frac{21}{50}\) \(\text{ т}\)
2. Mass for 5/7 m³:
   Mass = \(\frac{14}{25} \text{ т/м³}\) \(\times\) \(\frac{5}{7} \text{ м³}\)
Mass = \(\frac{14 \times 5}{25 \times 7}\) \(\text{ т}\)
Mass = \(\frac{70}{175}\) \(\text{ т}\)
   Simplifying the fraction: Divide both numerator and denominator by 35.
   Mass = \(\frac{2}{5}\) \(\text{ т}\)

Summary of Findings:

• The image displays several mathematical conditions for a variable 'b'.
• It poses a problem requiring the calculation of mass given the density of wood and two different volumes.
• The calculated masses are 21/50 tons for 3/4 m³ and 2/5 tons for 5/7 m³ of wood.